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luda_lava [24]
2 years ago
12

Suppose that c is the center of a circle with radius 13 in and a point p is at a distance of 32 in from

Mathematics
1 answer:
pantera1 [17]2 years ago
3 0
The sine of 1/2 the angle = 13 / 32

so this angle =  23.9695 degrees

Therefore the required angle = 2 * 23.9695  =  47.939  to 3 DP's. 

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1. Solve the system of equations: 2x + y = -2<br> 5x + 3y = -8
Fantom [35]

Answer: x=2 and y=−6

Step-by-step explanation: 2x+y=−2, 5x+3y=−8

2x+y=−2

2x+y+−2x=−2+−2x

y=−2x−2

5x+3y=−8

5x+3(−2x−2)=−8

−x−6+6=−8+6

−x=−2

−x /−1 = −2 /−1

x=2

y=−2x−2

y=(−2)(2)−2

y=−6

x=2 and y=−6

8 0
2 years ago
How can you solve quadratic equations in one variable?
ivolga24 [154]

you can use formular method or factorisation but formular method is easy and convinient

6 0
3 years ago
How do u simplify 5x^2-8x-12 subracted from -4x^2+2x-8
Nady [450]

Answer:

- 9x² + 10x + 4

Step-by-step explanation:

Calculate the subtraction as

- 4x² + 2x - 8 - (5x² - 8x - 12 ) ← distribute parenthesis by - 1

= - 4x² + 2x - 8 - 5x² + 8x + 12 ← collect like terms

= - 9x² + 10x + 4

7 0
2 years ago
LAST QUESTION! Please help! Please
prohojiy [21]
The correct answer is:  [C]:  " 37, 680 mm³ " .
________________________________________________________

Explanation:
________________________________________________________

The formula for the volume, "V" , of a cylinder is:

                →   V  =   \pi  *  r²  *  h  ;  

                           → in which "r = length of radius" ;  "h = height" ;             ________________________________________________________

     {Note that the formula for the volume, "V" , of a cylinder is:
     
                              →   " Base area * height " .
________________________________________________________

         →  Specifically, for a cylinder, the "Base area" is the area of a "circle", because the base is a circle;  

          →  and the formula for the "area of a circle = [tex] \pi [/tex] * r² " ;

          →  in which "r = length of the radius" . 

As such, the formula for the volume, "V" ,  of a cylinder is:
______________________________________________________
       →   Volume  =  (Base area) * (height) ; 

                             =  ( \pi r² ) * h  ;
______________________________________________________

       →   V  =  \pi  r²  h  
; 

                 in which:  "V = volume  {in "cubic units" ;  or, write as " units³ " } ;

                                  "r = radius length" ; 

                                  "h = height" ;
_____________________________________________________
  →  Now, we shall solve for the volume, "V", of the given cylinder in this question/problem:
_____________________________________________________

          →   V  = \pi  r²  h  ; 

                      in which: "r = radius = ? "  ; 

                        →  To find "r" ;  We are given the diameter, "d = 40 mm" ; 
 
                        →  Note that:  "r = d/2 = (40 mm) / 2 = 20 mm " ; 

                              {i.e., "the radius is half of the diameter".}.  

                        →  " r = 20 mm " ;  

                        →  " h = height = 30 mm " {given in figure) ; 
      
                        →  For \pi ; let us use " 3.14 " — which is a commonly used approximation.  

             →  For this question/problem, none of the answer choices are given "in terms of \pi " ;
     →   so we shall use this "numerical value" as an "approximation" ; 
_______________________________________________________

Now, let us plug in our known values into the formula;
     and calculate to find the volume, "V", of our given cylinder; as follows:
_______________________________________________________

    →    V  = \pi  r²  h  ; 

                =  (3.14) * (20 mm)²  * (30 mm) ; 

                =  (3.14) * (20)² *  (mm)²  * (30 mm) ;
          
                =  (3.14) * (20)² * (30) * (mm³) ;

                =  (3.14) * (400) * (30) * (mm³) ; 

                =  37, 680 mm³
__________________________________________________

The volume is
:  " 37, 680 mm³  " ;  

          →  which is:  Answer choice  [C]:  " 37, 680 mm³ " .
___________________________________________________
Hope this answer and explanation—albeit lengthy—is of some help to you.
Best wishes!
6 0
3 years ago
How would you measure the volume of a brick that contains holes
vaieri [72.5K]
In order to measure the volume of a brick that contains holes, what you need to do is to get the volume of both the brick as a whole, and the volume of the holes. Once you have the volume, you subtract the volume of the holes to the volume of the brick. The final answer would be the volume of a brick that contains holes. Hope this helps!
3 0
3 years ago
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