All you needed to do was plug in 5 into C
Answer:
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Step-by-step explanation:
Rearrange the equation to standard form of a quadratic equation (ax^2+bx+c=0) by switching sides: 5x^2+2x-12=0. Now, use the quadratic equation formula to solve. You should come out with x_1=sqrt61-1/5 and x_2=-1+sqrt61/5. Thus, your answer is B, or two solutions.
The domain and range is [-4, 4] and [0, 4]
<h3 /><h3>What is Domain and range?</h3>
The domain of a function is the set of values that we are allowed to plug into our function.
The range of a function is the set of values that the function assumes.
x² + y² = 16
y = √16 - x²
For domain under root should not be negative quantity,
16 - x²≥0
16≥x²
So, x≤4 or x≥4
Thus, the domain is [-4, 4]
Range:
y is maximum at x=0, y=4
y is minimum at x=4, y=0
Thus, range = [0, 4]
Learn more about domain and range here:
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Answer:
B
Step-by-step explanation: