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Bingel [31]
3 years ago
15

Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER

this is only half the test

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

1) The simplified radical form is  \sqrt{36x^2}=6x

2) The simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) The simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) The simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

Step-by-step explanation:

1) Given expression is \sqrt{36x^2}

To find the simplified radical form of the given expression :

\sqrt{36x^2}

=\sqrt{36\times x^2}

=\sqrt{36}\times \sqrt{x^2}

=\sqrt{6\times 6}\times \sqrt{x\times x}

=6\times x

\sqrt{36x^2}=6x

Therefore the simplified radical form is  \sqrt{36x^2}=6x

2)Given expression is \sqrt{72x^3}

To find the simplified radical form of the given expression :

\sqrt{72x^3}

=\sqrt{72\times x^3}

=\sqrt{72}\times \sqrt{x^3}

=\sqrt{9\times 8}\times \sqrt{x\times x\times x}

=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}

=3\times 2\sqrt{2}\times x\sqrt{x}

\sqrt{72x^3}=6x\sqrt{2x}

Therefore the simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) Given expression is \sqrt{15x^8}

To find the simplified radical form of the given expression :

\sqrt{15x^8}

=\sqrt{15\times x^8}

=\sqrt{15}\times \sqrt{x^8}

=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}

=\sqrt{15}\times x^4

\sqrt{15x^8}=\sqrt{15}x^4

Therefore the simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) Given expression is \sqrt{36x^7}

To find the simplified radical form of the given expression :

\sqrt{36x^7}

=\sqrt{36\times x^7}

=\sqrt{36}\times \sqrt{x^7}

=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}

=6\times x^3\sqrt{x}

\sqrt{36x^7}=6x^3\sqrt{x}

Therefore the simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

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