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Klio2033 [76]
3 years ago
10

I need help with this does anyone understand this?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer:

Let y = f(x)

=  > y =  \frac{19}{ {x}^{3} }

=  >  {x}^{3}  =  \frac{19}{y}

=  > x =   \sqrt[ 3]{ \frac{19}{y} }

{f}^{ - 1} (x) =   \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} }

<h2>option A</h2>
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