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3 years ago

10

I need help with this does anyone understand this?

1 answer:

soldier1979 [14.2K]3 years ago

4 0

Answer:

Let y = f(x)

$= > y = \frac{19}{ {x}^{3} }$

$= > {x}^{3} = \frac{19}{y}$

$= > x = \sqrt[ 3]{ \frac{19}{y} }$

${f}^{ - 1} (x) = \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} }$

<h2>option A</h2>

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ANSWER QUICK AND I WILL MAKE YOU BRAINLIEST

alekssr [168]

Answer:

The width of the window should be $7.6\ ft$ and the height of the window should be $3.8\ ft$

Step-by-step explanation:

we know that

The circumference of a semicircle (window) is equal to

$C=\pi r$

we have that

$C=12\ ft$

$\pi=3.14$

substitute and solve for r

$12=(3.14)r$

$r=12/3.14=3.8\ ft$

so

the width of the window is equal to the diameter of the semicircle

so

The width of the window should be $3.8*2=7.6\ ft$ and the height of the window should be $3.8\ ft$

4 0

3 years ago

Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 and one-t

NeTakaya

We have been given that Layana’s house is located at $(2\frac{2}{3}, 7\frac{1}{3})$ on a map. The store where she works is located at $(-1\frac{1}{3}, 7\frac{1}{3})$ .

We are asked to find the distance from Layana’s home to the store

We will use distance formula to solve our given problem.

Let us convert our given coordinates in improper fractions.

$2\frac{2}{3}\Rightarrow \frac{8}{3}$

$7\frac{1}{3}\Rightarrow \frac{22}{3}$

$-1\frac{1}{3}\Rightarrow -\frac{4}{3}$

Now we will use distance formula to solve our given problem.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of our given point in above formula, we will get:

$D=\sqrt{(\frac{22}{3}-\frac{22}{3})^2+(\frac{8}{3}-(-\frac{4}{3}))^2}$

$D=\sqrt{(0)^2+(\frac{8}{3}+\frac{4}{3})^2}$

$D=\sqrt{0+(\frac{8+4}{3})^2}$

$D=\sqrt{(\frac{12}{3})^2}$

$D=\sqrt{(4)^2}$

$D=4$

Therefore, the distance from Layana's home to the store is 4 units and option A is the correct choice.

3 0

3 years ago

Read 2 more answers

What is the volume of a box with a width 2 1/2 inches, length 1 3/4 inches, and height 3 1/4 inches?

enot [183]

Answer:

The volume of the box is 41.21 inches cube.

Step-by-step explanation:

Given,

Width of the box $2\frac{1}{2}$ inches

$=\frac{5}{2}$ inches

Length of the box $1\frac{3}{4}$ inches

$=\frac{7}{4}$ inches

Height of the box $3\frac{1}{4}$ inches

$= \frac{13}{4}$ inches

The box is in cuboid form.

The volume of cuboid is given by (length × breadth × height ).

So,

volume of the box is $( \frac{5}{2}$ × $\frac{7}{4}$ × $\frac{13}{4}$ $)$

= $( \frac{455}{32} )$

$= 14.21$ inches cube

The volume of the box is 41.21 inches cube.

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3 years ago

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marishachu [46]

Answer: 17 families

Step-by-step explanation:

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3 years ago

Need help with math equation

STALIN [3.7K]

Answer:

18x/18=36/18

x=2

Step-by-step explanation:

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3 years ago

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