B)

d)

9) I'm not really sure how to answer it, but I guess like 2.1, 2.2, 2.5, etc.,
10)


so {5, 6, 7, 8} is the answer
11) for some reason it won't let me insert a picture but put place

above 2, and then place

above 3, and then place

in between 2 and 3, but place it a little closer to three since

12) place

between 2 and three, but closer to two since

and also

and for number 13) the square root of 144 is 12, and the square root of 169 is 13, so any numbers between 12 and 13 will work.
I hope this helped and if not, message me and ill try to explain!
Answer:
35 quizzes
Step-by-step explanation:
We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.
We do this by using the formula
which describes the number of ways we can choose
objects given
possible choices. So, if
and
, then:

Hence, the teacher can make 35 different geometry quizzes.
I didn't get it can you post a picture with it too?
Answer:
So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
Step-by-step explanation:
In this data we have
Mean= u = 18
X= 38
Standard deviation = s= 6
1) We formulate the null and alternate hypothesis as
H0: u = 18 against Ha : u > 18 One tailed test .
2) The significance level alpha = ∝= 0.05 and Z alpha has a value ± 1.645 for one tailed test.
3)The test statistics used is
Z= X- u / s
z= 38-18/6= 3.333
4) The calculated value of z = 3.33 is greater than the z∝ = 1.645
5) So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
First we set the criteria for determining the true of value of the variable. That whether the rats learn in less or more than 18 trials.
Then we find the value of z for the given significance value given and the test about to be checked.
Then the test statistic is determined and calculated.
Then both value of z and z alpha re compared. If the test statistics falls in the rejection region reject the null hypothesis and conclude alternate hypothesis is true.
The figure shows that the calulated z value lies outside the given z values