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Llana [10]
3 years ago
7

3. A copy machine makes 60 copies per minute. A second

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

E

Step-by-step explanation:

6 x 480 + 8 x 60 = 960..........

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-8(-2 1/3)-(2(4) to the power of 2
maria [59]

Answer:

-13.333

Step-by-step explanation:

This is the answer to:

-8(-2 1/3)-(2(4) to the power of 2

Hope this helps!

6 0
2 years ago
Which statement about the graph f (x) = 2 (1)*
Bad White [126]
Third, the graph decreases from left to right because if you plug it into a graphing calculator - you can see that the line is a straight line, and does not decrease or increase whatsoever
4 0
3 years ago
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Marcus rented a movie for 4$ and some video games for $6 each he paid $22 how many games did he rent
galina1969 [7]

$22 - $4 (for the movie) = $18.

$18 / $6 (per game) = 3 games

8 0
3 years ago
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Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7
Zolol [24]
f(x)=\begin{cases}1&\text{for }-7

The Fourier series expansion of f(x) is given by

\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7

where we have

a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx
a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)
a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2

The coefficients of the cosine series are

a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx
a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)
a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}
a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}

When n is even, the numerator vanishes, so we consider odd n, i.e. n=2k-1 for k\in\mathbb N, leaving us with

a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}

Meanwhile, the coefficients of the sine series are given by

b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx
b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)
b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}
b_n=\dfrac{7(-1)^{n+1}}{n\pi}

So the Fourier series expansion for f(x) is

f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7
3 0
2 years ago
How many zeros are at the end of the product 25* 240?
SashulF [63]

Answer:Three zeros

Step-by-step explanation:

Just multiply them and see.  

6 0
3 years ago
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