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2 years ago

3. A copy machine makes 60 copies per minute. A second

Mathematics

1 answer:

Brums [2.3K]2 years ago

8 0

Answer:

Step-by-step explanation:

6 x 480 + 8 x 60 = 960..........

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Help with just 3 please.

svet-max [94.6K]

All you have to do is:

Make all of your fractions to common denominator.
Then, you add 8 3/10-1 2/5- 2 1/3+ 4 3/5
And when you solve it, you get 9 5/30 and when you simplify it,
You get 9 1/6 yards of ribbon

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3 years ago

Help show work pls for brisnly

Deffense [45]

Answer:

Step-by-step explanation:

Ok, so all we have to do is multiply 8 * 3/4, because each child needs 3/4 of the sandwich, and there are 8 of them. The easiest (My opinion) way to do this is by turning 8 into a fraction. Turning whole numbers into fractions is really simple, just slap a /1 under them to make them a fraction. And so, our fraction is 8/1. Now, all we have to do is multiply the top part of the fraction, and then the bottom part of the fraction. So, 8 * 3 = 24, and 1 * 4 = 4. So, just put 24/4 as an answer. But, wait! We have to simplify it! 24 divided by 4 is 6, so 6 is our final answer.

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3 years ago

Solve using substitutions! Help w this question please!!

Irina18 [472]

I hope this helps you

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3 years ago

The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max

siniylev [52]

Answer:

A) The maximum error in the calculated surface area: $25cm^2$

Relative error: $0.013$

B) The maximum error in the calculated volume: $162cm^2$

Relative error: $0.019$

Step-by-step explanation:

A) The formula for the surface area is:

$A=4\pi r^2$

The measured value is the circumference which is equal to:

$C=2\pi r$

then the radius is:

$r=\frac{C}{2\pi}$

Substituting in the formula of the surface:

$A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}$

Using the formula to calculate the error:

$dy=f'(x)dx$

Where $x$ is the variable measured and $y$ is a function of $x$ ( $y=f(x)$ ).

$dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC$

We have C=80cm and dC=0.5cm

$dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2$

The relative error is the maximum error divide by the total area. The total area is: $A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2$

$\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013$

B) The formula for the volume is:

$V=\frac{4}{3} \pi r^3$

Using $r=\frac{C}{2\pi}$

$V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}$

The maximum error is:

$dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2$