I believe the percentage is 33% of all kids i added all numbers table is a bit confusing
<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Hey there!
If we use pemdas:
P - Parentheses
E - Exponents
M - Multiplicatiom
D - Division
A - Addition
S - Subtractiom
We know we have to evaluate the exponent first. Two to the rid power is equal to 8. Therefore, we have:
2 - 4/2 + 8
Next, we do the division. -4/2 = -2, so we have:
2-2 + 8 = 0 + 8 = 8
Hope this helps!
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling
Nastasia [14]
<h3>
Answer: 1/12</h3>
This is because there's one side we want (that's labeled "8") out of 12 sides total. This is of course if each side is equally likely.
Side note: this 12-sided die is known as a dodecahedron.
Fat 6 of he eat sandwich and chocken
