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Agata [3.3K]
3 years ago
13

{{{{Help Please please}}}}

Mathematics
1 answer:
mixer [17]3 years ago
4 0

Answer:

Circles have equations such as: (x -h)² + (y -k)² = radius²

You need terms raised to the power of 2

Step-by-step explanation:

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right on edge

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\bf y=a(x-{{ h}})^2+{{ k}}\\
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the vertex of this one is at 0,1 and intercepts or "solutions" are at -1 and 1, so is opening downwards, notice the picture below

that means, the squared variable is the "x", thus the form is \bf y=a(x-{{ h}})^2+{{ k}}

now, we know the vertex is at 0,1, and two x-intercepts of \pm 1,0

thus      \bf y=a(x-{{ h}})^2+{{ k}}\qquad 
\begin{cases}
h=0\\
k=1\\
when
\\
x=\pm 1\\
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\end{cases}
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\textit{so.. hmmm let us use the point ... say hmmm 1,0}
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