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snow_lady [41]
3 years ago
11

Write an equation of the line that is perpendicular to the line y = 2x + 8, and which passes through the point (6,-2).

Mathematics
1 answer:
Doss [256]3 years ago
8 0
The answer should be y=-1/2x-14 :)
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A rectangle has a perimeter of 44 inches and an area of 72 square inches. What are the lengths of the sides of the rectangle?
kondor19780726 [428]
  • A rectangle has a perimeter of 44 inches and an area of 72 square inches.
  • Perimeter = 44 inches, area = 72 square inches.
  • Let the length and breadth be l and b respectively.
  • We know, perimeter of a rectangle = 2(l + b)
  • Therefore,
  • 2(l + b) = 44

or, l + b = 22

or, b = 22 - l ...(i)

  • We know, area of a rectangle = lb
  • Therefore,
  • lb = 72
  • Putting (i) in b, we get
  • l(22 - l) = 72

or, 22l - l^2 -72 = 0

or, l^2 - 22l + 72 = 0

or, l^2 - 4l - 18l + 72 = 0

or, l(l - 4) - 18(l - 4) = 0

or, (l - 4)(l - 18) = 0

or, l = 4 or l = 18

  • Therefore, if the length is 4 inches, then the breadth is (22-4) inches, i.e., 18 inches.
  • And if the length is 18 inches, then the breadth is (22-18) inches, i.e., 4 inches.

<u>Answer:</u>

<u>B)</u><u> </u><em><u>4</u></em><em><u> </u></em><em><u>inches </u></em><em><u>and </u></em><em><u>1</u></em><em><u>8</u></em><em><u> </u></em><em><u>inches.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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3 years ago
If b√2 = 6, what does b equal? I don't know why I'm stuck on this problem, but could somebody help me?
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Answer:

Step-by-step explanation:

Divide both sides by the square root of 2. If you are looking for an exact answer that is rationalized, it would be found by multiplying 6/sqrt(2) * sqrt(2)/sqrt(2) to get

b=\frac{6\sqrt{2} }{2}=3\sqrt{2}

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Your answer will be negative 2
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ollegr [7]

Answer:

so shes 26 meters above her home? i dont know what your asking tbh

Step-by-step explanation:

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Golf Scores In a professional golf tournament the players participate in four rounds of golf and the player with the lowest scor
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Mean scores.

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