Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:
In which a is the probability that a student takes calculus but not statistics and 
is the probability that a student takes both these classes.
By the same logic, we have that:
The probability of taking a calculus class and a statistics class is 0.07
This means that 
The probability of taking a statistics class is 0.90
This means that 
. So
The probability of a student taking a calculus class is 0.10
This means that 
What is the probability of a student taking a calculus class or a statistics class
93% probability of a student taking a calculus class or a statistics class
Answer: Area= 459.73cm^2
Step-by-step explanation: Circumference of a circle is 2πr
76=2×3.14×r
r= 76÷(6×3.14)
r=12.10
Area of a circle= πr^2
Area= 3.14×(12.10)^2
Area= 456.73cm^2
The answer is
1/3^3
And
1/27
And
3^-3
The answer is 5
9+6 = 15
15/3 is 5
Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
