Answer:
The histogram shows near normality,the sample is less than 10% of the population,however we don't know if sample is random or not.
With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that
![I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7B%5Csqrt%5B%5Cphi%5D%7Bx%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7B%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx%20%3D%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7Bx%5E%7B%5Cphi-1%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7Bx%20%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx)
Replace 
:
Split the integral at x = 1. For the integral over [1, ∞), substitute 
:
The integrals involving tan⁻¹ disappear, and we're left with
Answer:
Option A - 7.3.
Step-by-step explanation:
Given : Number 7.323.
To find : Which number is 7.323 rounded to the nearest tenth?
Solution :
Rounded to the nearest tenth rule :
1) If the hundredths place of a decimal is greater than or equal to five, then tenth place number is added by 1.
2) If the hundredths place of a decimal is less than five, then tenth place number does not change.
In the number 7.323
The Hundredth number is 2 < 5 so tenth number does not change.
7.323 rounded to the nearest tenth is 7.3.
Therefore, Option A is correct.
Answer:
72
Step-by-step explanation:
32pi×360/2pi(8)=72
central angle= arc length 360/2pi×r
Answer:
pretty sure it's 15 but if you used my answer and it was wrong srr
