Well, (m^2-7m-11) ÷ (m-8) = m+1 with a remainder of -3
AC = √(40²-12²) = √(1600-144) = √1456 = 4√91
tanA = 12/4√91 = 3/√91 = 3√91/91
option а.
Answer:
Option C
Step-by-step explanation:
we have
The compound inequality can be divided into two inequality
-----> inequality A
----> inequality B
Solve inequality A
Divide by -3 both sides
when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
Rewrite
The solution of the inequality A is the interval (-∞,-3]
Solve the inequality B
Divide by -3 both sides
when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
The solution of the inequality B is the interval [-6,∞)
The solution of the compound inequality is
[-6,∞) ∩ (-∞,-3]=(-6,-3]
Answer:
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