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sergey [27]
3 years ago
5

Someone please help me in this question it is kind of confusing it is a question under pre calculus in first year calculus i wil

l post the picture after this.. So the question is . The accompanying figure shows a rectangle inscribed in a isoceles right triangle whose hypotenuse is 2 units long.. a) Express the y-coordinate of P in terms of x (You might start by writing and equation for the line AB). . b) Express the area of the rectangle in terms of x.
Mathematics
1 answer:
masya89 [10]3 years ago
5 0
Neither P, nor A are on the sketch 
I guess P is the upper right corner of the rectangle 
and A=(0,1) 

P belongs to the line going through (1,0) and B(0,y) 
<span>but we don't know the y-coordinate of B </span>

<span>the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 </span>
now look at the right triangle BOA 
<span>his hypotenuse is AB=sqrt2 and the <span>the kathete</span> OA is 1 </span>
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1 
so the coordinates of B are (0,1) 

the line going through (1,0) and (0,1) is L(x)=-x+1 

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1) 

b) so if that's P, the height of the rectangle is -x+1 and the width=2x 
<span>so its area A(x)=2x*(-x+1)= -2x²+2x 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
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