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Answer with explanation</u>
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Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Set of hypothesis :
Confidence interval for population proportion is given by :-
, where
n= sample size
= sample proportion
and 
is the two-tailed z-value for confidence level (c).
As per given ,
Sample size of parents : n= 1085
Number of parents indicated that they were satisfied= 466
Sample proportion : 
Critical value for 90% confidence interval : 
( by z-value table)
Now, the 90% confidence interval :
Thus , the 90% confidence interval: (0.4043, 0.4537).
Since 0.43 lies in 90% confidence interval , it means we do not have enough evidence to reject the null hypothesis .
i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.
Answer:
The area is 31.5
Step-by-step explanation:
first you find the area of the rectangle (l x w) = 21
next you find the area of the triangle (b x h x 1/2) = 10.5
then you add the two areas together = 31.5
good luck with your khan academies :)
I think you have to find the value of x and y before u can simplify it.
Answer:
c i think
Step-by-step explanation:
Given that average age of employees of a large company is Normal
X - average age of employees
X:N(32,4)
The average age of employees in sales dept is 27 years.
Prob that an employee, chosen at random, will be younger than 27 years.
= P(X<27)
Let us convert x into Z
Z = (x-32)/4 = -5/4 = -1.25
Reqd prob = P(Z<-1.25) =0.5-0.3925
= 0.1075
Hence 10.56% is the correct answer.
