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LekaFEV [45]
3 years ago
7

There are 16 ounces in 1 pound juan is mailing a package that weighs 10 pounds

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer: 160 ounces

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

<em>16 ounces = 1 pound </em>

To obtain the weight in ounces of a package that weighs 10 pounds, we simply have to multiply the weight of 1 pound (16 ounces) by the number of ounces (10).

Mathematically speaking:

10pounds x 16 ounces /pounds = 160 ounces

exis [7]3 years ago
5 0
Ok so for 10 pounds there will be 160 ounces. To find the weight in ounces multiply 10 by 16. The number of pounds by the unit rate is 16 ounces per pound. Have a good day
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Step-by-step explanation:

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About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number
olganol [36]

Answer:

1) E(X) = np = 120*0.1 =12

SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286

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And we can use the normal approximation given by:

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And we can use the z score formula given by:

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And if we find the z score for 16 we got:

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And we can find this probability using the normal standard distribution or excel and we got:

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Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

X\sim Binom(n= 120 , p =0.1)

Part 1

The mean is given by:

E(X) = np = 120*0.1 =12

And the deviation would be:

SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

P(X\geq 16)

And we can use the normal approximation given by:

X \sim N(12, \sigma =3.286)

And we can use the z score formula given by:

z = \frac{X -\mu}{\sigma}

And if we find the z score for 16 we got:

z = \frac{16-12}{3.286}= 1.217

And we can find this probability using the normal standard distribution or excel and we got:

P(Z>1.217) = 0.112

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

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