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Alexeev081 [22]
4 years ago
9

*20 points* a coin is flipped 3 times and number of times heads appears is recorded. how many different outcomes can occur

Mathematics
2 answers:
8_murik_8 [283]4 years ago
6 0
There can only be two outcomes that result from the coon being flipped because there’s only two sides.
Sedaia [141]4 years ago
4 0
A) 2 

hope this helps ::)
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steven is makin burgers 1/3 of a pound each. if he has 6.02 pounds of meat how many burgers can he make
vodomira [7]

Answer:

20

Step-by-step explanation:

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Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3
andrew-mc [135]

Answer:

\frac{12x^4y^4}{3x^2y}=4x^2y^3

Step-by-step explanation:

Consider an element a\neq 0

We know that \frac{a^m}{a^n}=a^{m-n}

Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}

Here, we are required to divide 12x^4y^4 by 3x^2y.

Consider \frac{12x^4y^4}{3x^2y}

We will solve \frac{12}{3}\,,\,\frac{x^4}{x^2}\,,\,\frac{y^4}{y} separately.

Here,

\frac{12}{3}=4\\\frac{x^4}{x^2}=x^{4-2}=x^2\\\frac{y^4}{y}=y^3

So, \frac{12x^4y^4}{3x^2y}=4x^2y^3

8 0
3 years ago
Which of the following is a secant on the circle below?
boyakko [2]

A. \vec{KI} is the secant line on the below circle.

<u>Step-by-step explanation:</u>

The intersection of the circle will result in either Tangent or Secant. Secant is a line intersecting a circle at two different point. This concept explains the relation between the circle and line intersecting it.

From the given diagram,

The \vec{GJ} and \vec{GK} intersects the circle at the point H and I.

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3 years ago
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DaniilM [7]

Answer:

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murzikaleks [220]

Answer:

ME = t_{\alpha/2} \frac{s}{\sqrt{n}}

And the width for the confidence interval is given by:

Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval t_{\alpha/2} would be higher and then the width of the interval would increase. So then the best answer for this case would be:

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Step-by-step explanation:

Let's assume that we have a parameter of interest \mu who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say \bar X and for this particular example the confidence interval is given by:

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And the width for the confidence interval is given by:

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And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval t_{\alpha/2} would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

3 0
3 years ago
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