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Natasha2012 [34]
3 years ago
7

Help me pls help ..........

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

4

Step-by-step explanation:

(x)^2+(1/x)^2=18

(x-1/x)^2+2x.1/x=18

(x-1/x)^2+2=18

(x-1/x)^2=16

(x-1/x)^2=4^2

x-1/x=4

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One root of f(x) = 2x3 9x2 7x – 6 is –3. explain how to find the factors of the polynomial.
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<span>We have the following polynomial:

f(x)=2x^{3}+9x^{2}+7x-6

The problem states that one root is -3. Thus, it is true that (x+3) is a factor of the polynomial. Given that this is fulfilled, it is also true that:

</span>f(x)=(x+3)Q(x) \therefore Q(x)=\frac{f(x)}{x+3} \\ \\ where \ Q(x) \ has \ a \ degree \ of \ 2<span>

We can find Q(x) by applying Ruffini's rule, thus:

</span>\ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ 7 \ \ \ \ \ \ -6  \\ -3 \\ \rule{50mm}{0.1mm} \\ \ {} \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 3 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ 0<span>

Therefore:

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The roots of this polynomial can be get as follows:

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