Simplify completely 8x3+6x2-4x over -2x

Are the points B, F, and W coplanar?

Alla [95]

Where’s the picture of the angle?

4 0

3 years ago

Read 2 more answers

What is square root in simplified form? What is in simplified form?

Anon25 [30]

Answer:

Step-by-step explanation:

Let as us 45 as the number we should use to get the square root in the simplest form

And then 144

The square root of a number in is simplest form means to get the number inside the radical as low as possible

8 0

3 years ago

What % of 60 is 35?

STatiana [176]

Answer:

58.33%

Step-by-step explanation:

is %

-------- = ---------

of 100

Just plug in the numbers based on what it tells you.

What % = goes in the % spot

of 60 = goes in the of spot

is 35 = goes in the is spot

35 x

--------- = ---------

60 100

Cross multiply:

60 * x = 60x 35 * 100 = 3500

60x = 3500

Divide by 60 to get x by itself.

3500 / 60 = 58.33

Put the percent sign after it:

58.33%

I hope this helps.

8 0

3 years ago

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What's the answer to this?

Harman [31]

I'm pretty sure the answer is 40

6 0

3 years ago

I'm giving brainliest to the most helpful answer. For 50 points:

Alenkinab [10]

Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

4 0

3 years ago