Answer:
7
Step-by-step explanation:
1/7+1/3= 3/21+7/21= 10/21= 0.476190
the 6 digits after the decimal point get repeated
6*3= 18- three full cycles and the second digit after 3 cycles = 7 so the 20th digit is 7
Lol I’m tempted to steal these but I’m lazy
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Cot=cos\sin
sec=1\cos
cosx\sinx÷1\cosx=
cos^2x\sinx=1-sin^2x\sinx=
1\sinx-sin^2x\sinx= 1/sinx-sinx
We are given two points on a line. First we need to find the slope of the line using these two points.
The given points are (6, 1) and (5, 4). The slope (m) of the line will be:
Using the slope and the point (6,1) we can write the equation in point slope form as:
y - 1 = -3(x -6)
y = -3x + 18 + 1
y = -3x + 19
In standard form, the equation will be:
3x + y = 19
