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Fynjy0 [20]
4 years ago
15

Photo and Video Sharing. Photos and videos have become an important part of the online social experience, with more than half of

Internet users posting photos or videos online that they have taken themselves. Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves. Pew Research Center finds that P(A)=0.52,P(b)=0.26,, and P(AorB)=0.54. What is the conditional probability that an Internet user posts photos that they have taken themselves, given that they post videos that they have taken themselves? (Round your answer to three decimal places.)
Mathematics
1 answer:
love history [14]4 years ago
5 0

Answer: 0.923

Step-by-step explanation:

Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves.

Pew Research Center finds that

P(A)=0.52    P(b)=0.26,  and P(A or B)=0.54.

To find : P(A|B)

Since , \text{P(A or B)=P(A+P(B)-P(A and B)}

i.e. \text{P(A and B)=P(A)+P(B)-P(A or B)}

\text{P(A and B)=}0.52+0.26-0.54=0.24

Now, using conditional probability formula ,

P(A|B)=\dfrac{\text{P(A and B)}}{\text{P(B)}}\\\\=\dfrac{0.24}{0.26}=0.923076923077\approx0.923

Hence, the conditional probability that an Internet user posts photos that they have taken themselves, given that they post videos that they have taken themselves = 0.923

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You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s
fredd [130]

Answer:

Time spent rowing down stream =100\ seconds

Speed of boat in still water =14\ ms^{-1}

Step-by-step explanation:

Let speed of boat in still water be = x\ ms^{-1}

Speed of current = 10\ ms^{-1}

Speed of boat down stream = \textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}

Distance rowed down stream = 2400 m

Time spent rowing down stream = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s

Speed of boat up stream = \textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}

Distance rowed up stream = \frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m

Time spent rowing up stream = \frac{Distance}{Speed}=\frac{400}{x-10}\ s

We know that,

\textrm{Time spent rowing down stream =Time spent rowing up stream}

So,

\frac{2400}{x+10}=\frac{400}{x-10}

Cross multiplying

2400(x-10)=400(x+10)

Dividing both sides by 400

\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}

6(x-10)=x+10

6x-60=x+10

Adding 60 to both sides.

6x-60+60=x+10+60

6x=x+70

Subtracting both sides by x

6x-x=x+70-x

5x=70

Dividing both sides by 5.

\frac{5x}{5}=\frac{70}{5}

∴ x=14

Speed of boat in still water =14\ ms^-1

Time spent rowing down stream =\frac{2400}{14+10}=\frac{2400}{24}=100\ s

3 0
3 years ago
Solve for (f+g)(5) if f(x)=6x+3 and g(x)=x-4 show you work please
Diano4ka-milaya [45]
There are two ways to do this.

The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34

OR

you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34

Either way, the final answer is 34

7 0
4 years ago
Please help with math homework
frutty [35]

Answer:

240

Step-by-step explanation:

5 0
3 years ago
Find x using the picture below.
Katen [24]

Answer:

x ≈ 14.5

Step-by-step explanation:

A = x²√(25+10√5)/4

A = 1.72a²

x² = A/1.72

= 363.27/1.72

≈ 211

x = √211

≈ 14.5

6 0
3 years ago
Help me<br> and i will give you brainlost
Ronch [10]

Answer:

I'm not sure.

Step-by-step explanation:

But I will choose c.

45 MINUTES to run6 mile

4 0
3 years ago
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