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spayn [35]
3 years ago
9

Which is greater? 0.8 or 3/4

Mathematics
2 answers:
miskamm [114]3 years ago
7 0
0.8 is greater because 3/4 equals .75 
Vinil7 [7]3 years ago
7 0
0.8>3/4 3/4=0.75 0.75<0.8
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The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

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3 years ago
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Answer:

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Step-by-step explanation:

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0.5w = -7<br> pleasse help me
matrenka [14]

Answer:

The answer is -14.

Step-by-step explanation:

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3 years ago
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The domain of g(x) = 4x –12 is {2, 3, 6, 8}. What is the range
vlada-n [284]

Answer:

Range - {-4,0,12,20}

Step-by-step explanation:

Given that,

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Hence, the range of the function is {-4,0,12,20}.

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