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barxatty [35]
3 years ago
6

1 Canadian dollar to Japan

Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

77.00 Yen

Step-by-step explanation:

OLEGan [10]3 years ago
7 0

Answer:

77 Japanese Yen.

Step-by-step explanation:

The conversion is 1 Canadian dollar for every 77 Japanese yen.

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Olivia read a book. She started on page 20 and each minute she read 3 minutes. Let g(n) be the page Olivia was on at the beginni
miskamm [114]
If you mean each minute she read 3 pages.



If she started on page 20 and read 3 pages every minute, and the answer is how many pages did she read in 9 minutes.
Simple just do 20 x 9.

First step - what’s 2 x 9...18. Now anytime there’s a zero just simplify it by putting the 0 at the end of your answer. So the answer would be 180.

I hope this helped!!!
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A) 5/12×3=1 1/4 I know this for sure
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The measure of the supplement of an angle is 20° more than three times the measure of the original angle. find the measures of t
viva [34]

If the original angle is x degrees then its supplement is 180 - x degrees.

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3 years ago
What is a equation in slope intercept form for the line that has a slope -1 that passes through (-4,3)
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y=mx+b

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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

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Thus the weight in kilograms in 1980 is \frac{4k}{5}

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