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vladimir2022 [97]
3 years ago
11

What is a solution to (x + 6)(x + 2) = 60?

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

Ox=4

Step-by-step explanation:

expand he equation

x²+8x-48=0

using substitution method (of the options)

4 substituted as X eliminates all an results to zero

16+32-48=0

please mark brainliest

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Step-by-step explanation:

if you look at it it has the perfect pattern for a

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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
A business owner noted the features of the 100 cars parked at the business. Here are the results:
8_murik_8 [283]

Answer:

The probability of a selected car being a 4 door car, given that the car has a sunroof = 0.40

Step-by-step explanation:

The complete question is presented in the attached image.

The conditional probability, of event A happening, given that event B has happened, P(A|B), is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

So, the required probability of a selected car being a 4 door car, given that the car has a sunroof is given as

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

Note that the probability of an event is given as the number of elements in that event divided by the Total number of events.

P (4 doors n sunroof)

= n (4 doors n sunroof) ÷ n (total)

From the Venn Diagram in the attached image,

n (4 doors n sunroof) = 20 + 0 = 20

n (total) = 100

P (4 doors n sunroof) = (20/100) = 0.20

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n(total) = 100

P(sunroof) = (50/100) = 0.50

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

= (0.20/0.50) = 0.40

Hope this Helps!!!

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Answer:

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Step-by-step explanation:

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