Question

Can someone answer this?

Answer 1

You are told that the length of the pool is represented by x+14.  Dividing the volume (x^3 + 16x^2 + 13x - 210) by x+14 leaves you with x^2 +2x - 15, which represents the area of a cross section of the pool perpendicular to its length.

I used synthetic division with -14 as my first divisor; the result was  1  2  -15, which represents x^2 + 2 - 15.  This x^2 + 2 - 15 is easily factored (try using 3 as divisor in synthetic division); the factors are x-3 and x+5.

These results represent the width and the depth of the pool, not necessarily in that order.  However, the width is likely to be greater than the depth, so I would conclude that the width is x+5 and the depth is x-3.