A line passes through point (-6, -1) and is parallel to the equation y2x-5.

An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0

zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 105, p = 0.9$

So

$\mu = E(X) = np = 105*0.9 = 94.5$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07$

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{100 - 94.5}{3.07}$

$Z = 1.79$

$Z = 1.79$ has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

7 0

3 years ago

ILL BRAINLIEST YOU IF YOU GET IT RIGHT

IRINA_888 [86]

Answer:

b hope it helps make brainlliest ty

5 0

3 years ago

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ABC Corp. has outstanding accounts receivable totaling $6.5 million as of December 31 and sales on credit during the year of $24

Elden [556K]

Answer:

$378,000

Step-by-step explanation:

The computation of the bad debt expense for the year is shown below:

Bad debt expense = Outstanding account receivable × estimated percentage given - credit balance of allowance for doubtful account

= $6,500,000 × 0.06 - $12,000

= $390,000 - $12,000

= $378,000

We simply deduct the credit balance from the estimated balance so that the correct amount could arrive

3 0

3 years ago

A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost

Tanya [424]

So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
$\frac{6p}{3p^{2}}$ = $\frac{6}{3p}$ times $\frac{p}{p}$ = $\frac{2}{1p}$ times $\frac{p}{p}$ times $\frac{3}{3}$ = $\frac{2}{1p}$ times 1 times 1=2/p

easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1

each member pays 2/p

4 0

4 years ago

delilah studies the wolf population of a nearby national park. She has calculated that the population decreased by 1.25% per yea

KATRIN_1 [288]

Step-by-step explanation:

i need time

i hope u may understand

8 0

4 years ago

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