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3 years ago

Could someone please help me asap? Thanks in advance! :)

Mathematics

1 answer:

Elden [556K]3 years ago

4 0

Answer:

Step-by-step explanation:

the standard form of a quadratic equation is

ax² + bx + c = 0 : a ≠ 0

obtain (5 + x)(5 - x) = 7 in this form by expanding the factors

25 - x ² = 7 ( subtract 7 from both sides )

18 - x² = 0 ( multiply through by - 1 )

x² - 18 = 0 ← in standard form

with a = 1, b= 0 and c = - 18 → A

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Calculus 3 chapter 16

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Evaluate $\vec F$ at $\vec r$ :

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Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

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2 years ago

Find the quotient. 5/6 divided by 1/6

Montano1993 [528]

Answer:

5 × 6

6 × 1

30 ÷ 6

6 ÷ 6

= 5

the awnser would be 5

Step-by-step explanation:

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3 years ago

Read 2 more answers

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (You can use the probab

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The area to the right of z = 1.35 is 0.0885 and the area to the left of -0.47 is 0.3192.

<h3>How to compute the values?.</h3>

Given z = 1.35

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= 0.0885

The area to the left of -0.47 will be:

= 1 - P(z < 0.47)

= 1 - 0.6808

= 0.3192

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Answer:

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3 years ago

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3 years ago