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Brums [2.3K]
2 years ago
5

Anyone know the answer?

Mathematics
1 answer:
aleksklad [387]2 years ago
3 0
I want to say it’s the second one
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Nesecito ayuda con esta operación <br> ( -1/5 +2/5) +4/7
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No se la respuesta lo siento
6 0
3 years ago
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Subtracting mixed number 4_1 - 2_7 4 8 4
aleksandr82 [10.1K]

Answer:

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

Step-by-step explanation:

Given

4\frac{1}{4} - 2\frac{7}{8} --- proper representation of the question

Required

Evaluate

Convert numbers to improper fractions

4\frac{1}{4} - 2\frac{7}{8} = \frac{17}{4} - \frac{23}{8}

Take LCM

4\frac{1}{4} - 2\frac{7}{8} = \frac{34 - 23}{8}

4\frac{1}{4} - 2\frac{7}{8} = \frac{11}{8}

Convert to improper fraction

4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}

8 0
3 years ago
during a bike challenge, riders have to collect various colored ribbons. each 1/2 mile they collect a red ribbon, each 1/8 mile
Natali [406]
<span><u><em>The correct answer is: </em></u>
green and blue.

<u><em>Explanation</em></u><span><u><em>: </em></u>
We want to see which fractions </span></span>\frac{3}{4} is a multiple of. We know that \frac{3}{4} is a multiple of \frac{1}{4}, because \frac{1}{4}*3=\frac{3}{4}.

We can divide fractions to determine if \frac{3}{4} is a multiple of \frac{1}{2}:
\frac{ \frac{3}{4}}{ \frac{1}{2}};

in order to divide fractions, flip the second one and multiply:
\frac{3}{4})*\frac{2}{1}=\frac{6}{4}=1 \frac{1}{2}.
This did not divide evenly, so \frac{3}{4} is not a multiple of 1/2.

Checking to see if \frac{3}{4} is a multiple of \frac{1}{8}, \frac{ \frac{3}{4}}{ \frac{1}{8}};

flip the second one and multiply:
\frac{3}{4}*\frac{8}{1}=\frac{24}{4}=6.
This divided evenly, so \frac{3}{4} is a multiple of \frac{1}{8}.
6 0
3 years ago
Read 2 more answers
How do I find the critical points?
podryga [215]
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

\frac{d}{dx}(x^{2} - 1)^{3}

So we apply chain rule:

= 3(x^{2} - 1)^{2} * 2x

Set our first derivative to zero and solve for x:

3(x^2 - 1) * 2x = 0

So we can see that (by plugging in) 0, -1 and 1 makes our solution true

So our critical value is x = 0, x = -1, x = 1
5 0
3 years ago
This is what I meant on my last question. sorry​
Zigmanuir [339]

Answer:

its C

Step-by-step explanation:

4 0
3 years ago
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