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Otrada [13]
3 years ago
11

Algebra homework please help

Mathematics
2 answers:
densk [106]3 years ago
5 0

Answer:

So do you want the roots? If so it is

x  ≈  −

1.37049747

, 1.13336413

but rounded is x = -1 ; x = 1

Step-by-step explanation:

kondor19780726 [428]3 years ago
5 0

Answer:

Asympnotes:

Vertical:       x = -1

Horizontal:   none

You might be interested in
What is the answer for 5/2 and it is equal to 1/3
Fofino [41]

Answer:

5/2=2.5, while 1/3= aprox 0.333, therefore 5/2 is not equal to 1/3.

Step-by-step explanation:

Here is the long division table for 5/2

 2. 5 0 0

2 5. 0 0 0

− 4      

 1 0    

− 1 0    

   0 0  

 −   0  

     0 0

   −   0

       0

Here is the long division table 1/3 ( to three decimal places)

0. 3 3 3

3 1. 0 0 0

− 0      

 1 0    

−   9    

   1 0  

 −   9  

     1 0

   −   9

       1

An easier way to do 5/2 is to think of 50/2, which is 25, and then add a decimal point, making it 2.5.

An easier way to do 1/3 is to think of it as one third (of one), or 0.333 repeating.

6 0
3 years ago
Order the values from smallest (top) to largest (bottom) 1. 5 2/3 2. 5 1/6 3. 4 5/6 4. 4 1/2 5. 4 1/3 6. 5 6/6
Ulleksa [173]
4 1/3, 4 1/2, 4 5/6, 5 1/6, 5 2/3, 5 6/6
6 0
3 years ago
How would you write5 x 5 x 5 x 5 as a numerical expression using exponential notation ?
katen-ka-za [31]
5^4 is the answer!!!!!!!!!
8 0
3 years ago
Read 2 more answers
Lucy recieves a gift of a twenty-one year annuity on the day she was born. The annuity pays $500 on her odd birthday and $700 on
suter [353]

Explanation:

Let i represent the nominal annual interest rate (8%). Then the effective annual multiplier of the principal is ...

  (1 +i/12)^12 = (1+.08/12)^12 ≈ 1.0829995

Then the 2-year multiplier is the square of this:

  1+r = (1.0829995)² = 1.1728879

We can use the formula for the present value of an annuity to refer all of the odd-birthday payments to 1 year prior to birth, then adjust by the above annual multiplier. All the even-birthday payments will have the formula applied in the usual way.

  PV = P(1 -(1+r)^-n)/r

where P is the payment amount, (1+r) is the periodic multiplier, and n is the number of payments.

For the odd-birthday payments, the PV (1 year early) is ...

  PV = $500(1 -(1.1728879)^-11/0.1728879 = $2391.5704

so, the amount referred to the day of birth is ...

  1.0829995 × $2391.5704 = $2590.07 . . . . . PV of odd-birthday payments

__

The value of even-birthday payments is ...

  PV = $700(1 -(1.1728879)^-10/0.1728879 = $3227.06

And the total value of both sets of payments is ...

  annuity value = $2590.07 +2337.06 = $5817.13

_____

<em>Alternate solution</em>

You could also work this using the PV formula on the sum of ten sets of two years' payments: (700 +500/1.083) and then add the PV of the first odd-year birthday payment: 500/1.083.

This gives ...

  500/1.083 + (700 +500/1.083)(1 -(1.1729^-10))/0.1729 = 5817.13

3 0
4 years ago
How do you solve 8/11(n-10)=64
krek1111 [17]

Answer:

n = 98

Step-by-step explanation:

8/11 x (n - 10) = 64

multiply both sides of the equation by 11/8

11/8 x 8/11 x (n-10) = 11/8 x 64

reduce the numbers with greatest common divisor 11

1/8 x 8 (n-10) = 11/8 x 64

n - 10 = 11 x 8

multiply the numbers

n - 10 = 88

so then you add the numbers

n = 88 + 10

n= 98


6 0
3 years ago
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