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3 years ago

El área de un decágono regular cuya apotema mide 5,08 cm y la longitud de su lado es 3,3 cm.

Mathematics

1 answer:

jeyben [28]3 years ago

4 0

Answer:

83.82 cm^2

Step-by-step explanation:

Aquí, queremos calcular el área de un decágono dada su apotema y la longitud de su lado.

Matemáticamente;

Área de decágono = 1/2 * perímetro * apotema

Donde perímetro = 10 * s

donde s es la longitud de los lados

Entonces el área aquí sería; 1/2 * 10 (3.3) * 5.08 = 83.82 cm ^ 2

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seropon [69]

We need to solve for the height of the tree and we need to define the variable that would represent this value. In this case, we assign "y" for the unknown height of the tree. See attached picture for better comprehension.
Solving for the variable "a" which is base of downhill to the tree, we have it:
cos 20° = a / 15 ft
a = 15*cos 20°
a = 14.095 feet
Solving for the variable "x" which is the side of the hill to the base of the tree, we have it:
sin 20° = x / 15 ft
x = 15 * sin20°
x = 5.130 feet
Solving for the variable "y", which is the height of the tree, we have it:
tan 45° = (x+y) / a
tan 45° = (5.13 + y) / 14.095
y = 14.095*tan45° - 5.13
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The height of the tree is 8.965 feet.

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3 years ago

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Free_Kalibri [48]

Answer:

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7 0

2 years ago

Trey sold t-shirts and hats at a festival. His total profit was $106. He made a $4 profit for each t-shirt he sold. He also made

marta [7]

Answer:

18 t-shirts.

Step-by-step explanation:

Trey made a total profit $106 by selling t-shirts and hats. $34 of that profit was from selling hats, subtract 34 from 106 and you will get 72. So he made a profit of $72 in selling t-shirts. The t-shirts were $4 each, so if you divide 72 by 4 you will get 18. Meaning he sold 18 shirts.

5 0

3 years ago

3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0

Naya [18.7K]

Answer:

Step-by-step explanation:

The quadratic formula of a quadratic equation

$ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}$

$\text{If}\ b^2-4ac$

We have:

$x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5$

5 0

3 years ago

You work for a city department which is hosting a 5 kilometer run. Your coworker measured the course and doing that it is only 4

MAVERICK [17]

Answer:

820 feet

Step-by-step explanation:

We can use the rule of three in this scenario since this is a ratio problem with one unknown. To do this we simply multiply the diagonal values and divide by the final value. We know that there are a total of 3280.84 ft in a single kilometer, therefore...

1 km == 3280.84 ft

0.25 == x

(0.25 * 3280.84) / 1 = 820.21

Now we can see that there are 820.21 ft in the 0.25 kilometers. If we round this to the nearest foot we would round down to a total of 820 feet.

4 0

2 years ago