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tiny-mole [99]
3 years ago
12

HELP QUICK PLZ I AM STUCK!!!!!!!

Mathematics
1 answer:
Rasek [7]3 years ago
3 0

Answer:

B.  

Step-by-step explanation:

First move the x with negative exponent to the bottom, leaving the x term on the bottom which cancels out collectively the x terms in the numerator.  Then just multiply it out

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Ludmilka [50]

15%×60=

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A corporate team-building event costs $2 for every attendee. Write an equation that shows the relationship between the attendees
nasty-shy [4]

Answer:

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6 0
2 years ago
PLEASE ANSWER ASAP!!!!
Arlecino [84]

We'll use the notation \textrm{Arcsin } x for the principal value and \arcsin x for all the values:


\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k


Part I


\sin(\theta/2) = \frac 1 2


\theta/2 = \arcsin \frac 1 2


Part II. In our range we can write


\sin(\theta/2) = \sin(\frac \pi 6)


\theta/2 = \frac \pi 6 \textrm{   or   } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}


Part III.


\theta = \frac \pi 3 \textrm{   or   } \theta = \frac{5\pi}{3}


Part IV.


\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k

\theta = \frac \pi 3 + 4 \pi k \textrm{   or   } \theta = \frac{5 \pi}{3} + 4\pi k  \quad \textrm{integer } k



5 0
2 years ago
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