HELP QUICK PLZ I AM STUCK!!!!!!!

Mathematics

1 answer:

Rasek [7]3 years ago

3 0

Answer:

Step-by-step explanation:

First move the x with negative exponent to the bottom, leaving the x term on the bottom which cancels out collectively the x terms in the numerator. Then just multiply it out

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HELP PLEASEEE

ivanzaharov [21]

Answer:

1. 4

2. 16

3. 4/3

4. 64/3

Step-by-step explanation:

3 0

3 years ago

Please help thank you.

Mnenie [13.5K]

Answer:

Option D

Step-by-step explanation:

Whenever we take a square root of a number the ± sign is with it like here in the question

$x^2=20\\\\Apply\ square\ root\ on\ both\ sides\\sqrt{x^2}=\sqrt{20} \\\\The\ square\ cancels\ out\ with\ the\ root\x=\sqrt{20}$

And then x = ±4.47 which means x has two values one is +4.47 and the other is -4.47 so Option D is our answer.

7 0

3 years ago

Please help! [99 points]

anygoal [31]

This is a linear function.

A linear function is a straight line that has a slope, and follows the formula: <em>
y = mx + b</em>

In which:
y = y
m = slope
x = x
b = y -intercept

hope this helps<em />

4 0

3 years ago

Read 2 more answers

Pls help me answer this :'(

anzhelika [568]

Answer:

I believe the answer is D :)

4 0

3 years ago

V=r^2+R^2h; Solve for R

Ne4ueva [31]

Solve for R by simplifying both sides of the equation, the isolating the variable.
R^2h=-r^2+v

6 0

3 years ago