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Anna007 [38]
3 years ago
15

The equation h = -16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown

upward. How many seconds after the ball is thrown will it reach its maximum height? What is its maximum height?
Mathematics
1 answer:
belka [17]3 years ago
6 0
<span>It would take 1 second to reach its maximum height, which would be 25 feet.

h=<span><span><span>−<span>16<span>(<span>1^2</span>)</span></span></span>+<span><span>(32)</span><span>(1)</span></span></span>+<span>9 If you substituted t as 1, you would find that after simplification, h would be 25.

You would find out that as you increased t, h would get smaller.
</span></span></span>
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