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Angelina_Jolie [31]
3 years ago
10

Can I get help with number 16.

Mathematics
1 answer:
pychu [463]3 years ago
8 0
All of these points have the same y coordinate so this is a horizontal line which has a slope of 0.
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2 * M = X
M = to minutes
x = to how many tables washes
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3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
3 years ago
Help me solve for X
Vinil7 [7]

Answer:

Step-by-step explanation:

Opposite angles equal each other, so angle B and angle D are equal.

2x = 74

x = 37

5 0
3 years ago
Give the coordinates of the point located halfway between (2,1) and (2,4).
nordsb [41]
((X1+x2)/2,(y1+y2)/2) ---> ((2+2)/2,(1+4)/2) ---> (2,2.5)
8 0
3 years ago
What is the product of Five-ninths and Seven-eighths?
Rom4ik [11]

Answer:

Improper fraction form:103/72 Mixed number form: 1 32/72 Decimal form: 1.4035 with 5 repeating

Step-by-step explanation:

3 0
3 years ago
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