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3 years ago

Divide: (-4x^3+35x+25)÷(-2x-5)

Mathematics

2 answers:

aleksklad [387]3 years ago

6 0

Okay. After some work here is the answer I got.

Hoped I Helped. Have A Wonderful Day. :)

Mamont248 [21]3 years ago

4 0

Answer: The required answer is $2x^2-5x-5.$

Step-by-step explanation: We are given to divide the following algebraic fraction :

$F=\dfrac{-4x^3+35x+25}{-2x-5}.$

We will try to write the cubic numerator as a product of a linear factor (denominator) and a quadratic factor.

The simplification is as follows :

$F\\\\=\dfrac{-4x^3+35x+25}{-2x-5}\\\\\\=\dfrac{-(4x^3-35x-25)}{-(2x+5)}\\\\\\=\dfrac{4x^3-35x-25}{2x+5}\\\\\\=\dfrac{2x^2(2x+5)-5x(2x+5)-5(2x+5)}{2x+5}\\\\\\=\dfrac{(2x+5)(2x^2-5x-5)}{(2x+5)}\\\\=2x^2-5x-5.$

Thus, the required answer is $2x^2-5x-5.$

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