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3 years ago

The length of a rectangle is 1 ft less than 3 times the width. The area is 310 ft^2. Find the dimensions of the rectangle.

Mathematics

1 answer:

alexdok [17]3 years ago

5 0

Answer:

Length = 32 ft

Width = 10 1/3 ft

Step-by-step explanation:

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Piecewise function help

Vlad1618 [11]

Nothing is mentioned...how am I supposed to help you?

3 0

3 years ago

Find the circumference of this figure. Show your calculations.

solong [7]

Answer:

Circumference of circle= 37.68 units

Circumference of sector= 6.28 units

Step-by-step explanation:

The given figure is a circle with given radius OB= 6 units.

The circumference of a circle is the total length of its boundary.

For the complete circle its circumference can be calculated by;

Circumference= $2\pi r$

$=2*3.14*6\\=37.68$ units

For the circumference of the Sector with 60° in the figure, the circumference can be calculate by:

$=\frac{60}{360}* 2*\pi*6\\\\=\frac{1}{6}*12*3.14\\\\ =2*3.14\\\\=6.28$ units

So, the circumference of the full circle is 37.68 units and the circumference of the sector is 6.28 units.

5 0

3 years ago

Omg please help please

Brut [27]

$x^{2}$ Answer:

(Explanation)

Step-by-step explanation:

Part A:

The graph of y = $x^{2}$ + 2 will be translated 2 units up from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate left.

This is what graph A should look like:

[Attached File]

Part B:

The graph of y = $x^{2}$ - 2 will be translated 2 units down from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate right.

This is what graph B should look like:

[Attached File]

Part C:

The graph of y = 2 $x^{2}$ is a stretched version of the graph y = $x^{2}$ . Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

This is what graph C should look like:

[Attached File]

Part D:

The graph of y = $\frac{1}{2}x^{2}$ is a compressed version of the graph y = $x^{2}$ . Numbers that are in-between 0 and 1, and -1 and 0 are compressed.

This is what graph D should look like:

[Attached File]

4 0

4 years ago

In 1990, the cost of tuition at a large Midwestern university was $99 per credit hour. In 2003, tuition had risen to $268 per cr

vodka [1.7K]

Answer:

63%

Step-by-step explanation:

From the question, we aim to find the percent increase in the tuition

Given data

initial cost= $99 per credit hour

Final cost= $268 per credit hour

% increase= (Final - initial )/initial *100

substitute

% increase= (268- 99 )/268 *100

% increase= 169 /268 *100

% increase= 0.630*100

% increase= 63%

Hence the increase in the tuition from 1990 to 2003 is 63%

5 0

3 years ago

Solve for x in the equation X^2 - 8X + 41= 0

BaLLatris [955]

Answer:

The equation has two solutions for x:

x₁ = (8 + 10i)/2

x₂ = (8 - 10i)/2

Step-by-step explanation:

Let's use the quadratic formula for solving for x in the equation:

X^2 - 8X + 41= 0

x² - 8x + 41 = 0

Let's recall that the quadratic formula is:

x = -b +/- (√b² - 4ac)/2a

Replacing with the real values, we have:

x = 8 +/- (√-8² - 4 * 1 * 41)/2 * 1

x = 8 +/- (√64 - 164)/2

x = 8 +/- (√-100)/2

x = 8 +/- (√-1 *100)/2

Let's recall that √-1 = i

x = 8 +/- 10i/2

x₁ = (8 + 10i)/2

x₂ = (8 - 10i)/2

8 0

3 years ago