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frosja888 [35]
4 years ago
8

A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou

sly at the top of an inclined plane and do not slip, which one will reach the bottom first?
Mathematics
1 answer:
artcher [175]4 years ago
3 0

Answer:

Solid Sphere

Step-by-step explanation:

According to the question, the three shapes have equal masses (m), radii (R) (and diameter).

The shape with the least mass moment of inertia will have the highest acceleration

Let IC represents Inertia

According to calculations, the inertia of

Solid Sphere: IC=(2/5)mR²

Solid Cylinder: IC=½mR²

Hollow Pipe: IC=⅔mR²

Where m = mass of the shape

And R is the Radius of the shape

By comparison, the solid sphere has the least mass of inertia and hollow Pipe has the most mass of inertia.

So, solid sphere will get to the bottom first.

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9x+2

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Area of Parallelograms, Quadrilaterals, and Polygons - Quiz - Level F What is the area of this triangle? in. in2 Ich h = 5 in. b
algol13

The area of the triangle with a base of 10in and height of 5in is 25 square inches

<h3>How to find the area of a triangle</h3>

A triangle is a to dimensional shape with 3 sides and angles

Area of a triangle = 0.5bh

<h3>Given the following parameters</h3>

base = 10in

height = 5 in

<h3>Substitute the given parameters into the formula</h3>

A = 0.5 * 10 * 5

A = 25 square inches

Hence the area of the triangle with a base of 10in and height of 5in is 25 square inches

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3 0
2 years ago
Hi! Can anyone please help me with is math problem?Please show the steps on how you got your answer. Thank you!
WINSTONCH [101]

Answer: Marianne would have to get a 79 on her final test.


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3 years ago
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