Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
Answer:
B y = -1/2x + 7/2
Step-by-step explanation:
We know that it has a negative slope since the points go from the top left to the bottom right
We can eliminate A and D
The y intercept is where it crosses the y axis
It should cross somewhere between 2 and 4
C has a y intercept of 9 which is too big
Lets verify with a point
x = -4
y = -4(-4)+9 = 16+9 = 25 (-4,25) not even close to being near the points on the graph
checking B
y = -1/2 (-4) +7/2
= 2 + 7/2 = 11/2 = 5.5 it seems reasonable
3 times 6 18 and do that 6 times add
Answer:
y = c/b - (A x)/b
Step-by-step explanation:
Solve for y:
A x + b y = c
Hint: | Isolate terms with y to the left hand side.
Subtract A x from both sides:
b y = c - A x
Hint: | Solve for y.
Divide both sides by b:
Answer: y = c/b - (A x)/b
Answer:
True
Step-by-step explanation:
If two events X and Y are mutually exclusive,
Then,
P(X∪Y) = P(X) + P(Y)
Let A represents the event of a diamond card and B represent the event of a heart card,
We know that,
In a deck of 52 cards there are 4 suit ( 13 Club cards, 13 heart cards, 13 diamond cards and 13 Spade cards )
That is, those cards which are heart can not be diamond card,
⇒ A ∩ B = ∅
⇒ P(A∩B) = 0
Since, P(A∪B) = P(A) + P(B) - P(A∩B)
⇒ P(A∪B) = P(A) + P(B)
By the above statement,
Events A and B are mutually exclusive,
Hence, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually exclusive event is a true statement.
