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Natalija [7]
3 years ago
13

Chapter

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answers:

1) 18x - 6x + 2x = 14x

Combine like terms by subtracting 6 from 18 and adding 2

2) 4b - 7 - 15b + 3 = - 11b - 4

Combine like terms add 4b and - 15b ; add -7 and 3

3) 15(6-g) = 90 - 15g

Distribute the 15 to both terms

4) -24 + 2(y - 9) = 2y - 42

Distribute the 2 to (y-9) and combine like terms

   

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What is the point estimate for the number of cars sold per week for a sample consisting of the following weeks: 1, 3, 5, 7, 10,
Romashka [77]
Hi.
your answer is c: 6.38 but the actual answer of your question is 11.
hope this helps!!!
5 0
3 years ago
Read 2 more answers
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

H_0: The true average penetration is 50 mils

H_a: The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the <em>level of confidence</em> is α = 0.05 then the z_\alpha score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

z=\frac{\bar x-\mu}{s/\sqrt{n}}

where

\bar x = <em>mean of the sample</em>

\mu = <em>average established by the specification</em>

s = <em>standard deviation of the sample</em>

n = <em>size of the sample</em>

Computing this value of z we get z = 3.42

Since z >z_\alpha we can conclude that the sample has not met the required specification.

5 0
3 years ago
The 90% confidence interval for the mean one-way commuting time in New York City is
Zinaida [17]

Answer:

95% provides more information

Step-by-step explanation:

The confidence interval is obtained by using the relation :

Xbar ± Zcritical * σ/√n

(Xbar - (Zcritical * σ/√n)) = 5.22 - - - (1)

(Xbar + (Zcritical * σ/√n)) = 5.98 - - (2)

Adding (1) and (2)

2xbar = 5.22 + 5.98

2xbar = 11.2

xbar = 11.2 / 2 = 5.6

Margin of Error :

Xbar - lower C.I = Zcritical * σ/√n

Zcritical at 90% = 1.645

5.6 - 5.22 = 1.645 * (σ/√n)

0.38 = 1.645 * (σ/√n)

(σ/√n) = 0.38 / 1.645 = 0.231

Therefore, using the se parameters to construct at 95%

Zcritical at 95% = 1.96

Margin of Error = Zcritical * σ/√n

Margin of Error = 1.96 * 0.231 = 0.45276

C.I = xbar ± margin of error

C. I = 5.6 ± 0.45276

C.I = (5.6 - 0.45276) ; (5.6 + 0.45276)

C. I = (5.147 ; 6.053)

Hence, 95% confidence interval provides more information as it is wider.

3 0
3 years ago
A store sells 4 main types of chocolate bars milk chocolate dark chocolate white chocolate and hazelnut chocolate the store empl
sergij07 [2.7K]
Hi there! The answer is A. 252

To find the percentage of the customers who preferred the milk chocolate bar we need to know two things:

First we need to know the total amount of customers, which is 50.
Second we need to know how many of these customers preferred the milk chocolate bar. This bar is preferred by 28 people.

Now we can fill in the following formula, in order to find our percentage:
\% = \frac{part}{total} \times 100 \% = \frac{28}{50} \times 100 \% = 0.56 \times 100 \% = 56 \%

Now we can multiply this percentage by the total amount of chocolate bars which will be bought (which is 450).
56 \% \times 450 = 0.56 \times 450 = 252

Hence, the answer is A. 252
~ Hope this helps you!
7 0
3 years ago
Standard firm for 400,000+60,000+5,000+100
SVETLANKA909090 [29]

465,100

four hundred thousand + sixty thousand + five thousand + one hundred

8 0
3 years ago
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