3px = 2q(r-5x)
distribute
2qr - 10qx
3px = 2qr - 10qx
To solve for x
add 10qx to both sides
3px + 10qx = 2qr
factor out x
x(3p+10q) = 2qr
divide both sides by 3p+10q to isolate x
x = 2qr / <span>(3p+10q)
Hope this helps :)</span>
We know that the area of a circle in terms of π will be πr². However the area with respect to the diameter will be a different story. The first step here is to find a function relating the area and diameter of any circle --- ( 1 )
For any circle the diameter is 2 times the radius,
d = 2r
Therefore r = d / 2, which gives us the following formula through substitution.
A = π(d / 2)² = πd² / 4
<u>Hence the area of a circle as the function of it's diameter is A = πd² / 4. You can also say f(d) = πd² / 4.</u>
Now we can substitute " d " as 4, solving for the area ( A ) or f(4) --- ( 2 )
f(4) = π(4)² / 4 = 16π / 4 = 4π - <u>This makes the area of circle present with a diameter of 4 inches, 4π.</u>
160000000 =
move the decimal so only one number is to the left
we need to move it 8 times
1.60000000 *10^8
1.6*10^8
58413000000
move the decimal so only one number is to the left
5.8413000000 * 10^10
5.8413*10^10
Answer:
7x+y, when x+4 and y+5
7(4) + 5=
28+5=
33
Step-by-step explanation:
Hope this helps. :)
