What is 10 divided by 587?

Write in slope-intercept form an equation of a line that passes through the points (-1,2) and (1,-6)

creativ13 [48]

Answer: y = 6 - 4x

Step-by-step explanation: Find the slope: (y2-y1) / (x2-x1). In this case, [2-(-6)] / (-1-1) = 8/-2 = -4. Then write it in intercept form, substituting in a point for y and x: 2 = a -4(-1). Then balance to get a = 6. So y = 6 - 4x

3 0

3 years ago

Evaluate b2 c -1 for b = 8 and c = -4.

jok3333 [9.3K]

-80
hope this helps
vote me brainliest

6 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through the pair of points. (1.8, –3.4), (6.8, –8.4)

elixir [45]

Answer:

-1

Step-by-step explanation:

If a straight line passes through the known points (x1, y1) and (x2, y2), the its slope is given by $m = \frac{y1-y2}{x1-x2}$

Now, in our case the straight line passes through the points (1.8, - 3.4) and (6.8, - 8.4).

Therefore, the slope of the required straight line will be $m = \frac{-3.4-(-8.4)}{1.8-6.8}= -1$ ( Answer )

3 0

4 years ago

How do you solve the equation y=2x^2+6x-80 for solution sets?

Pani-rosa [81]

Answer:

x

−

5

=

0

and

x

+

8

=

0

.

x

=

5

,

−

8

idk why it looks like that xD

:3

6 0

3 years ago

The lateral surface area of cone A is exactly 1/2 the lateral surface area of cylinder B. Cone A radius is r and height h - Cyli

Mrac [35]

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$ . (Correct choice: False)

<h3>What is the ratio of lateral area of cone to the lateral area of the cylinder?</h3>

In accordance with space geometry, the lateral areas of the cone and cylinder are described by the following equations:

Cone

$A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}$ (1)

Cylinder

$A_{l} = 2\pi\cdot r\cdot h$ (2)

If we divide (2) by (1), then we have the following ratio:

$r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$ . (Correct choice: False)

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

3 0

2 years ago