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algol13
1 year ago
8

Find an equation of line with given slope and y-intercept. Slope= -6 y-intercept= (0,-10) The equation of the line is: ?

Mathematics
1 answer:
GREYUIT [131]1 year ago
4 0

Step-by-step explanation:

so, we find the slope-intercept form :

y = ax + b

"a" is the slope (it is always the factor of x), "b" is the y-intercept (the y-value when x = 0).

we have the slope : -6

and the given point (0, -10) gives us already the y-value when x = 0 : -10

therefore, the equation is

y = -6x - 10

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2 years ago
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3 years ago
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cricket20 [7]

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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

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or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

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Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

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Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

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