A store sells wrapping paper for $3, greeting cards for $2, and ribbon for $1. The soccer

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

4 0

Answer:

A) (15 x $3) + (10 x $2) + (12 x $1) = X

B) $77

Step-by-step explanation:

A) Each wrapping paper is 3 dollors, and they bought 15 (15 x 3)

Each greeting card is 2 dollors, and they bought 10 (10 x 2)

Each roll of ribbon is 1 dollors, and they bought 12 (12 x 1)

B) 15 times 3 is 45

10 times 2 is 20

12 x 1 is 12

45 + 20 + 12 = 77

You might be interested in

What are the number of integral solutions of the equation 2x+2y+z=20 such that x>=0 , y>=0 , z>=0?

zaharov [31]

$2x+2y+z=20\\
z=\dfrac{20}{2x+2y}\\
z=\dfrac{10}{x+y}$

Now, for z to be an integer, the sum x+y must be a divisor of 10.
It has to be a positive divisor since z≥0. Also x≠y.

$x+y=1 \\
x=1-y\\
$
x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.

$x+y=2\\
x=2-y\\$
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.

$x+y=5\\
x=5-y$
y can be 0,1,2,3,4 or 5 - 6 solutions

$x+y=10\\
x=10-y$
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.

2+2+6+10=20 solutions in total.

6 0

2 years ago

Find three consecutive natural numbers if the square of the smallest number is 65 less than the product of the remaining two num

Vedmedyk [2.9K]

Answer:

21, 22, and 23

Step-by-step explanation:

Three consecutive natural numbers can be represented as n, n+1, and n+2.

The square of the smallest number would be $n^2$ and its equal to the product of the other two (n+1)(n+2).