Answer:
V = 15.6 m/s
Explanation:
using the equation of motion
v = u + at
v = 0 + 5.2(3)
v = 15.6 m/s
Answer:
The answer is "The air will move faster on the narrow side".
Explanation:
The air on the top slows down in hypertensive. This is why light travels quicker on top. This results in air deflection downwards, required for its energy conservation to generate lift, and that is why air has to be moved quicker on the narrow side by the very same airflow per unit time as it departs.
Answer:
B, B (decreases, a clockwise)
Explanation:
Finally, the switch on the electromagnet is reopened. The magnitude of the external magnetic flux through the wire loop <u>decreases</u>, and there is <u>a clockwise</u>, current induced in the loop (as seen from the left).
<span>The acceleration of an object is directly proportional to the force applied to it and .... Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg .... If a 1-N net force accelerates a 1-kg mass at 1 m/s2, what is the acceleration ... 30 000 kg, in takeoff when the thrust for each of its four engines is 30 000 N?</span>
Answer:
The intralveolar pressure is 1 mmHg
Explanation:
The transpulmonary pressure is the difference between the alveolar pressure and the intrapleural pressure. It is this gradient between pressures that allows the air to flow during human ventilation.
Writing this into an equation it means that, Ptp = Palv - Pip, so from there we have Palv = Ptp + Pip, or Palv = 5 mmHg - 4 mmHg = 1 mmHg.