Calculate the acceleration of a 1400-kg car that stops from 39 km/h "on a dime" (on a distance of 1.7 cm).
1 answer:
Answer:
Explanation:
The car is under an uniforly accelerated motion. So, we use the kinematic equations. We calculate the acceleration from the following equation:
We convert the initial speed to
The car stops, so its final speed is zero. Solving for a:
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Answer:
267 m
Explanation:
v=λf
v= m/s
λ=?
f=Hz
λ
λ=267 m
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Answer:
45.9m
Explanation:
Given parameters:
Final velocity = 30m/s
Initial velocity = 0m/s
Unknown:
Height of fall = ?
Solution:
The motion equation to solve this problem is given below;
V² = U² + 2gH
V² = 0 + (2 x 9.8 x H)
30² = 19.6H
H = = 45.9m
Answer:
θ=142.9°
Explanation:
d=1 *r
angle ϕ= 37.1°
the line connecting pebble and target should be tangent to a circle so
cos(180-ϕ-θ)==
∴ θ=180-ϕ-
θ= 180-37.1-0
θ=142.9°
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