The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
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Answer:
for completing the square it would be
however if you were to find the roots it would
be
however the picture is unclear on what to do so these may help
Step-by-step explanation:
easy question answer but I don't do this
well you have to see how far they have gotten after 4 hours. so 4*40=160 50*4=200. since it was opposite directions you add. so 160+200=360.
4/50 as a decimal is .08
Divide 4 by 50
