Answer:
x = 1
y = 3
Step-by-step explanation:
<h2>
<em><u>Substitution Method</u></em><em><u>:</u></em></h2>
Step 1:
Name The Equation
4x + y = 7 ...(1)
3x + 2y = 9 ...(2)
Step 2:
From Equation (1) we get,
4x = 7 - y
i.e.,
x = 7 - y/4
Step 3:
Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)
i.e.,
3(7 - y/4) + 2y = 9
21 - 3y/4 + 2y = 9
21 - 3y + 8y/4 = 9
21 - 3y + 8y = 9 * 4
21 + 5y = 36
5y = 36 - 21
5y = 15
y = 15/5
<em><u>y = 3</u></em>
Step 4:
Substitute the value of <em><u>y = 3</u></em> in equation (1)
4x + y = 7
i.e.,
4x + (3) = 7
4x + 3 = 7
4x = 7 - 4
4x = 4
x = 4/4
<em><u>x = 1</u></em>
<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>
4x + y = 7 i.e., <em>4(1) + (3) = 7</em>
3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>
Answer:
y = 3^(1 + x)
Step-by-step explanation:
Notice that each time x increases by 1, y increases by a factor of 3.
Thus, the required equation has the form y = 3^x.
Check: If x = 0, do we get 3? No. Therefore we must modify the exponent:
y = 3^(1 + x)
Check: If x = 0, do we get 3? 3^(1 + 0) = 3 (correct)
If x = 2, do we get 27? 3(1 + 2) = 3^3 + 27 (correct)
Answer: Part A: she would make 35.75
Part B: She would work for 7 hours
Step-by-step explanation:
Part A: $6.50+4.5=35.75
Part B: $45.50 dived by $6.50 would be 7. So she worked 7 hours
Answer:
F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(3) = 3(3)^2 + 1 = 27 + 1 = 28
G(4) = 2(4) - 3 = 8 - 3 = 5
2H(5) = 2(5) = 10
F(3) + G(4) - 2H(5) = 28 + 5 - 10
F(3) + G(4) - 2H(5) = 23
Step-by-step explanation:
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