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2 years ago

A music store purchases a grand

Mathematics

2 answers:

alukav5142 [94]2 years ago

7 0

Answer: 8250

Step-by-step explanation:

shtirl [24]2 years ago

4 0

Answer:

8548

Step-by-step explanation:

You might be interested in

Triangle QRS has vertices Q(-4,2),R(3,0), and S(4,3).

Dafna1 [17]

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

Vectorially speaking, a point is translated to another location on Cartesian plane by means of this expression:

$A'(x,y) = A(x,y) + T(x,y)$ (1)

Where:

$A(x,y)$ - Original point.
$A'(x,y)$ - Translated point.
$T(x,y)$ - Translation vector.

If we know that $Q(x,y) = (-4,2)$ , $R(x,y) = (3,0)$ , $S(x,y) = (4, 3)$ and $R'(x,y) = (7, -6)$ $T(x,y) = (4, -6)$ , then the coordinates of the vertices of the triangle $Q'R'S'$ are:

$Q'(x,y) = Q(x,y) + T(x,y)$

$Q'(x,y) = (-4,2) + (4,-6)$

$Q'(x,y) = (0, -4)$

$R'(x,y) = R(x,y) + T(x,y)$

$R'(x,y) = (3,0) +(4,-6)$

$R'(x,y) = (7,-6)$

$S'(x,y) = S(x,y) + T(x,y)$

$S'(x,y) = (4, 3) + (4, -6)$

$S'(x,y) = (8, -3)$

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

We kindly invite to see this question on translations: brainly.com/question/17485121

5 0

3 years ago

Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the following data values: 560,

julsineya [31]

Answer:

z-score for value 560 = 0.6

z-score for value 650 = 1.5

z-score for value 500 = 0

z-score for value 450 = -0.5

z-score for value 300 = -2

Step-by-step explanation:

We are given a sample with a mean of 500 and a standard deviation of 100.

i.e., $\mu$ = 500 and $\sigma$ = 100

The z score distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where X represents the data values;

So, z score for value 560 is;

z score = $\frac{560-500}{100}$ = 0.6

So, z score for value 650 is;

z score = $\frac{650-500}{100}$ = 1.5

So, z score for value 500 is;

z score = $\frac{500-500}{100}$ = 0

So, z score for value 450 is;

z score = $\frac{450-500}{100}$ = -0.5

So, z score for value 300 is;

z score = $\frac{300-500}{100}$ = -2

7 0

3 years ago

Write a quadratic function F whose zeros are 12 and 1

Solnce55 [7]

Answer:

$f(x) = (x-12)(x-1)$

Step-by-step explanation:

So when you have a quadratic equation it can usually be expressed as: $a(x-b)(x-c)$ where b and x are the roots of the equation. Since it's just asking for a function whose zeroes are 12 and 1, I'm assuming it doesn't care about the stretch/compression (value of a determines that), so I'll just assume a=1. if 12 and 1 are zeroes, that means it makes one of the factors equal to 0 because is x-b = 0 then no matter the value of x-c the value of y is 0 because 0 * (x-c) will be 0. So the equation becomes $f(x) = (x-12)(x-1)$ plugging in 12 or 1 as x will make one of the factors 0 thus making f(x) equal to 0