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posledela
4 years ago
6

Michael translates ABCDE Complete the table of ordered for the preimage and image.

Mathematics
1 answer:
vovikov84 [41]4 years ago
3 0
Bruh im just tryna find the answers
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Simora [160]
I know that from least to greatest is C
The decimal as a percent is A
36% as as a fraction is C
8% as a decimal is A
7/8 as a percent is B
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4 years ago
Read 2 more answers
¿Se puede afirmar que América es un conti-<br> nente poco poblado? ¿Por qué?
notka56 [123]

Answer:

El continente que se considera poco poblado debido a que su población ocupa menos de la mitad de su territorio es AMÉRICA.

Aunque no lo pareciera tenemos que el continente americano es considerado como poco poblado, pero esto es por la distribución de las sociedades que por falta de población.

La distribución de los pueblos americanos es bastante ortodoxa y esto ha hecho que las poblaciones se concentren en sitios y que ocupen menos territorio en el continente. Ademas, hay que tomar en cuenta que existe muchos territorios naturales que no se pueden poblar por ejemplo la amazonia.

Step-by-step explanation:

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3 years ago
16 Use the Empirical Rule. (Do not use technology. Technology will give a slightly different answer.)
kotykmax [81]

Answer:

a)8.4kg to 10.6kg

b)7.3 kg to 11.7kg

c)16%

d) 95%

e) 0.15%

Step-by-step explanation:

The empirical rule formula states that:

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

From the question,

Mean(μ) = 9.5 kg,

Standard Deviation (σ) = 1.1 kg.

a) 68% of the data is between which 2 values?

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

μ - σ

= 9.5kg - 1.1kg

= 8.4kg

μ + σ

= 9.5kg + 1.1kg

= 10.6kg

Therefore, 68% of the data is between 8.4kg to 10.6kg

(b) 95% of the data is between which 2 values?

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ - 2σ

9.5kg - 2(1.1)kg

9.5kg - 2.2 kg

= 7.3kg

μ + 2σ

9.5kg + 2(1.1)kg

9.5kg + 2.2 kg

= 11.7kg

Therefore, 95% of the data is between 7.3 kg to 11.7kg

(c) What percentage of the data is less than 8.4 kg?

We need to find how many standard deviations from the mean 8.4kg is, in order to know the percentage it falls under

μ - xσ = 8.4kg

= 9.5kg - 1.1x = 8.4kg

9.5 - 8.4 = 1.1x

1.1 = 1.1x

x = 1.1/1.1

x = 1

Hence, the percentage it falls under according to Empirical rule = 68%

The percentage of the data that is less than 8.4 kg is calculated as:

100 - 68/2 = 32/2 = 16%

(d) What percentage of the data is between 7.3 kg and 11.7 kg?

We have to find the Standard deviation that they fall under

For 7.3 kg

μ - xσ = 7.3kg

= 9.5kg - 1.1x = 7.3kg

9.5 - 7.3 = 1.1x

2.2 = 1.1x

x = 2.2/1.1

x = 2

μ + xσ = 11.7kg

= 9.5kg + 1.1x = 11.7kg

11.7 - 9.5 = 1.1x

2.2 = 1.1x

x = 2.2/1.1

x = 2

Therefore, based on the calculation above and the empirical formula rule, the percentage of the data is between 7.3 kg and 11.7 kg is 95%

(e) What percentage of the data is more than 12.8 kg?

μ + xσ = 12.8kg

9.5kg + 1.1x = 12.8kg

= 12.8- 9.5 = 1.1x

3.3 = 1.1x

3.3 = 1.1x

x = 3.3/1.1

x = 3

Hence, the percentage it falls under according to Empirical rule = 99.7%

The percentage of the data that is more than 12.8kg is calculated as:

100 - 99.7/2 = 0.3/2 = 0.15%

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MA_775_DIABLO [31]
18 i think that’s what it would be
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7 questions correct that they got correct

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