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alexandr1967 [171]
3 years ago
7

I hate math bro please help me ill mark u brainliest

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
Please mark me brainless :)
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Solve for x, show all of your work:<br><br> -2x – 4 &lt; 10
algol [13]
-2x -4<10
      +4   +4
-2x <14
  x>-7
8 0
3 years ago
I dont know this i dont understand can someone help me? please thank you​
emmasim [6.3K]

Answer:

hope that will help you

7 0
3 years ago
Engineers at a large automobile manufacturing company are trying to decide whether to purchase brand A or brand B tires for the
andre [41]

Answer:

s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526

t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844  

p_v =2*P(t_{22}  

Comparing the p value with a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.  

Step-by-step explanation:

Data given and notation

\bar X_{A}=37900 represent the mean for A

\bar X_{B}=39800 represent the mean for B

s_{A}=5110 represent the sample standard deviation for A

s_{B}=5900 represent the sample standard deviation for B

n_{A}=12 sample size for the group A  

n_{B}=12 sample size for the group B

\alpha Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the means are equal or not, the system of  hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{B}= 0  

Alternative hypothesis:\mu_{A} - \mu_{B}\neq 0  

We don't have the population standard deviation's but we assume that the population deviation is equal for both populations, so we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{s_p\sqrt{\frac{1}{n_{A}}+\frac{1}{n_{B}}}} (1)  

Where s_p represent the standard deviation pooled given by:

s_p =\sqrt{\frac{(n_A -1)s^2_A +(n_B -1)s^2_B}{n_A +n_B -2}}

s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844  

P value  

We need to find first the degrees of freedom given by:

df=n_A +n_{B}-2=12+12-2=22

Since is a two tailed test the p value would be:  

p_v =2*P(t_{22}  

Comparing the p value with a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.  

6 0
3 years ago
Find the range of this equation
Rzqust [24]

Answer:

b number

Step-by-step explanation:

Because range is the number of the y component

8 0
3 years ago
Read 2 more answers
Can someone please help me with this square root problem?
nadya68 [22]

Answer:

x=14.87

Step-by-step explanation:

What we want to use is pythagoras theorem:

a^2+b^2=c^2, where c is the hypotenuse

10^2+11^2=x^2

221=x^2

x=\sqrt{221}

x=14.866...

x=14.87

4 0
2 years ago
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