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alexandr1967 [171]
3 years ago
7

I hate math bro please help me ill mark u brainliest

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
Please mark me brainless :)
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What is the greatest common factor (GCF) of 88 and 132?
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The linear combination method is the same as the elimination method.  Let's multiply the second equation by -2 so the x terms cancel each other out. When we do that we get a system of 2x-3y=13 and -2x-4y=8.  The x-terms cancel each other out giving us -7y=21 and y = -3.  Now sub -3 into one of the equations to solve for x.  x+2(-3)=-4, and x - 6 = -4.  x = 2.  So the solution for our system is (2, -3)
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the diagram shows a rectangle is 13 cm the area of the rectangle is 93.6 cm calculate the width of the rectangle.
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7.2 cm

Step-by-step explanation

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3 0
3 years ago
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What is the area of the trapezoid?
Maslowich
<h3><u>Given Information :</u></h3>

  • Length of parallel sides = 60 ft and 40 ft
  • Height of the trapezoid = 30 ft

<h3><u>To calculate :</u></h3>

  • Area of the trapezoid.

<h3><u>Calculation :</u></h3>

As we know that,

\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\

  • a and b are length of parallel sides.
  • h denotes height.

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>valu</em><em>es</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>:

\longmapsto Area = \sf \dfrac{1}{2} × ( 60 + 40 ) × 30 ft\sf ^2

\longmapsto Area = \sf \dfrac{1}{2} × 100 × 30 ft\sf ^2

\longmapsto Area = 1 × 100 × 15 ft\sf ^2

\longmapsto Area = 100 × 15 ft\sf ^2

\longmapsto <u>Area = 1500 ft</u>\sf ^2

Therefore,

  • Area of the trapezoid is <u>1500 ft\sf ^2</u>

6 0
2 years ago
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