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scoundrel [369]
3 years ago
11

Explain the difference between using the tangent ratio to solve for a missing angle in a right triangle versus using the cotange

nt ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view. (10 points)

Mathematics
1 answer:
Lena [83]3 years ago
4 0

Answer:

While determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other.

Step-by-step explanation:

See the diagram attached.

Let us assume a right triangle Δ ABC with ∠ B = 90°. Now, assume that the angle ∠ CAB = \theta and the sides AB, BC, CA are 3, 4, 5 units respectively.

The tangent ratio of an angle \theta is given by  

\tan \theta = \frac{BC}{AB} = \frac{4}{3}  

Again, the cotangent ratio of angle \theta is given by  

\cot \theta = \frac{AB}{BC} = \frac{3}{4}  

Therefore, in both the cases of tangent ratio and cotangent ratio are inverse of each other and while determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other. (Answer)

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Round to the nearest tenth.
inessss [21]

Answer: Angle A = 53.9 degrees

Step-by-step explanation: We have a right angled triangle with two sides clearly given and one angle to be calculated. If the angle to be calculated is angle A, then having angle A as our reference angle, line AC (10 units) is the adjacent, line CB is the opposite while line AB (17 units) is the hypotenuse. Having been given the adjacent and the hypotenuse, we can now use the trigonometric ratio as follows;

CosA = adjacent/hypotenuse

CosA = 10/17

CosA = 0.5882

By use of the calculator or table of values,

A = 53.97

Approximately to the nearest tenth,

A = 53.9 degrees

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3 years ago
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Let f(x) = 2x^2 +3x-4 find f(3h)
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substitute x = 3h into f(x)

f(3h) = 2(3h)² + 3(3h) - 4 = (2 × 9h²) + 9h - 4 = 18h² + 9h - 4


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Arrange the steps to solve the equation square root x+3 - square root 2x-1=-2
stiv31 [10]

Answer:x=31.4919

Step-by-step explanation:

Step1:isolate a square root on the left hand side√x+3=√2x-1-2

Step2:eliminate the radicals on the left hand side

Raise both sides to the second power

√x+3)^2=(√2x-1-2)^2

After squaring

x+3=2x-1+4-4-4√2x-1

Step3:get the remaining radicals by itself

x+3=2x-1+4-4√2x-1

Isolate radical on the left hand side

4√2x-1=-x-3+2x-1+4

4√2x-1=x

Step4:eliminate the radicals on the left hand side

Raise both side to the second power

(4√2x-1)^2=x^2

After squaring

32x-16=x^2

Step 5:solve the quadratic equation

x^2-32x-16

This equation has two real roots

x1=32+√960/2=31.4919

x2=32-√960/2=0.5081

Step6:check that the first solution is correct

Put in 31.4919 for x

√31.4919+3=√2•31.4919-1-2

√34.492=5.873

x=31.4919

Step7:check that the second solution is correct

√x+3=√2x-1-2

Put in 0.5081 for x

√0.5081+3=√2•0.5081-1-2

√3.508=-1.873

1.873#-1.873

One solution was found

x=31.4919

6 0
3 years ago
3 ^ 2 x * 3 - 4 * 3 ^ x + 1 equals 0<br><img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B2x%20%2B%201%7D%20%20%20-%204%20%5Ctim
Sophie [7]


Explanation just use gauth.math
Hope this helps

Answer:

6 0
3 years ago
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