Question

In a single-server queuing system, if 12 customers arrive per hour with Poisson distribution and 30 customers are served per hour with a negative exponential distribution. The system utilization is: - 1) 0.4 2) 0.02. 3) 0.06 4) 0.27

Answer 1

Answer:

0.4

Step-by-step explanation:

λ= number of arrival per unit time

μ= number of customers served per unit time

now we know that

System Utilization  = $\frac{\lambda }{\mu }$

in our case it is given that

λ= 12 per hour

and μ= 30 customers served per hour

therefore  system utilization=  $\frac{12 }{30 }$

= 0.4

hence the final answer is 0.4

hope this helps