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SOVA2 [1]
3 years ago
12

Roger went shoe shopping with his cousins Derek and Kamal. Roger bought a pair of basketball shoes that cost $74.95. Derek spent

$24.55 more than Roger on a pair of running shoes. Kamal bought the same running shoes as Derek. Since he had a coupon, Kamal paid 4/ 5 as much as Derek for the shoes. How much money did Kamal spend on running shoes?
Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

I'm pretty sure its $19.65

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What does "B" stand for in the volume formula?
Morgarella [4.7K]
B stands for Area of the base in the volume formula
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2 years ago
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I need help with the the answer please, i don’t know it
geniusboy [140]
When you multiply 6 by 600 it equals 3,600 
6x600=3,600
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3 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
I NEED HELP!!!!!! 4x+2x-5=7x-1
yan [13]

Let's solve your equation step-by-step.

4x+2x−5=7x−1

Step 1: Simplify both sides of the equation.

4x+2x−5=7x−1

4x+2x+−5=7x+−1

(4x+2x)+(−5)=7x−1(Combine Like Terms)

6x+−5=7x−1

6x−5=7x−1

Step 2: Subtract 7x from both sides.

6x−5−7x=7x−1−7x

−x−5=−1

Step 3: Add 5 to both sides.

−x−5+5=−1+5

−x=4

Step 4: Divide both sides by -1.

−x

−1

=

4

−1

x=−4

Answer:

x=−4

i hope this helps you

3 0
2 years ago
“x is at most –5 or at least 7.”
uysha [10]
<span>x is at most –5 or at least 7 is written as x  \leq -5  \ or \ x \geq 7</span>
7 0
2 years ago
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