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Alexeev081 [22]
3 years ago
9

I need some help with this question

Mathematics
1 answer:
Tems11 [23]3 years ago
7 0

Check the picture below.

namely, is the volume of the rectangular prism Paraffin, equals or less than the volume of the cone made from it?

\bf  \textit{volume of a rectangular prism}\\\\ V=Lwh~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=8\\ w=6\\ h=4 \end{cases}\implies V=8\cdot 6\cdot 4\implies \boxed{V=192} \\\\[-0.35em] ~\dotfill\\\\ \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5\\ h=25 \end{cases}\implies V=\cfrac{\pi (5)^2(25)}{3}\implies \boxed{V\approx 654.5}

well, clearly the cone has enough room to take the 192 cm³.

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It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

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Step-by-step explanation:

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