Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,


t = 1.875 seconds
Put the values of t in equation (1). So,

h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
Answer:
(1, 3)
Step-by-step explanation:
If quadrilateral ABCD is reflected across the line y = x, then the x- and y-coordinates get reversed. Since the coordinates of point D are (3, 1), then the coordinates of point D' are (1, 3).
5,10,15,20,25,30,35,40,45,50,55,60,65,70,75, 80,85,90,95,100 and so on
In the table it shows that 1 hour corresponds to $25. Or if you want to check it, simply take any value and divide it by its corresponding hour ( ex. 50/2 or 75/3) Hope this helps!